A) 9.33 cal
B) 10.21 cal
C) 12.67 cal
D) 13.34 cal
Correct Answer: A
Solution :
Work done = Force × Displacement\[=\mu \ mg\times (v\times t)\] \[W=(0.2)\times 2\times 9.8\times 2\times 5\ joule\] Heat generated Q\[=\frac{W}{J}\]\[=\frac{0.2\times 2\times 9.8\times 2\times 5}{4.2}\]\[=9.33\]calYou need to login to perform this action.
You will be redirected in
3 sec