A) 32 m
B) 24 m
C) 16 m
D) 12 m
Correct Answer: C
Solution :
For given condition\[s\propto \frac{1}{{{m}^{2}}}\]\[\therefore \]\[\frac{{{s}_{2}}}{{{s}_{1}}}={{\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right)}^{2}}={{\left( \frac{200}{300} \right)}^{2}}\] Þ \[{{s}_{2}}={{s}_{1}}\times \frac{4}{9}=36\times \frac{4}{9}=16\ m\]You need to login to perform this action.
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