A) \[{{\overline{KE}}_{CO}}={{\overline{KE}}_{{{N}_{2}}}}\]
B) \[{{\overline{KE}}_{CO}}>{{\overline{KE}}_{{{N}_{2}}}}\]
C) \[{{\overline{KE}}_{CO}}<{{\overline{KE}}_{{{N}_{2}}}}\]
D) Cannot be predicted unless the volumes of the gases are given
Correct Answer: A
Solution :
For same temp. kinetic energies would be equal for all molecules, what ever their molecular weights will be, it doesn't matter.You need to login to perform this action.
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