A) The average translational KE per molecule is the same in \[{{N}_{2}}\] and \[C{{O}_{2}}\]
B) The rms speed remains constant for both \[{{N}_{2}}\] and \[C{{O}_{2}}\]
C) The density of \[{{N}_{2}}\] is less than that of \[C{{O}_{2}}\]
D) The total translational KE of both \[{{N}_{2}}\] and \[C{{O}_{2}}\] is the same
Correct Answer: A
Solution :
Kinetic energies per molecule will be same because it is proportional to absolute temperature only. \[\frac{{{d}_{{{N}_{2}}}}}{{{d}_{C{{O}_{2}}}}}=\frac{{{M}_{{{N}_{2}}}}}{{{M}_{C{{O}_{2}}}}}=\frac{28}{44}\]i.e. \[d{{N}_{2}}<dC{{O}_{2}}\] Total translational kinetic energy will also be same because at same temperature & pressure number of molecules present in same volume would be same (according to Avogadro's Law)You need to login to perform this action.
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