A) 3
B) \[\frac{3}{2}\]
C) 1
D) 0
Correct Answer: A
Solution :
\[\underset{x\to 2}{\mathop{\lim }}\,\,\,\frac{{{x}^{3}}-8}{{{x}^{2}}-4}\], \[\left( \frac{0}{0}\,\text{form} \right)\] Applying L-Hospital's rule, we get \[\underset{x\to 2}{\mathop{\lim }}\,\,\,\frac{3{{x}^{2}}}{2x}=\underset{x\to 2}{\mathop{\lim }}\,\,\,\frac{3\times 2\times 2}{2\times 2}=3\].You need to login to perform this action.
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