A) 3
B) 9
C) 18
D) 21
Correct Answer: D
Solution :
Let \[y=\underset{x\to 3}{\mathop{\lim }}\,\,\,\frac{{{x}^{3}}-{{x}^{2}}-18}{x-3}\], \[\left( \frac{0}{0}\,\text{form} \right)\] Applying L-Hospital's rule, we get \[y=\underset{x\to 3}{\mathop{\lim }}\,\,\,3{{x}^{2}}-2x=(27-6)=21\].You need to login to perform this action.
You will be redirected in
3 sec