A) 0
B) 1
C) 2
D) Infinitely many
Correct Answer: D
Solution :
(d): \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{4}{2}=2,\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{-6}{-3}=2,\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{18}{9}=2\] \[\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}}\] \[\therefore \]Coincident lines \[\Rightarrow \]Infinitely many solutions.You need to login to perform this action.
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