A) \[4\times {{10}^{4}}V\]
B) \[2\times {{10}^{4}}V\]
C) \[2\times {{10}^{2}}V\]
D) \[1\times {{10}^{4}}V\]
Correct Answer: D
Solution :
(d) \[1\times {{10}^{4}}V\] Here, current \[l=\frac{V}{R}=\frac{10}{5}=2\,A\] Final current, when the switch is opened becomes zero. \[\therefore \frac{dl}{dt}=\frac{0-2}{2\times {{10}^{-3}}}=-1\times {{10}^{3}}A\,{{s}^{-1}}\] As \[\varepsilon =-L\frac{dl}{dt}=-10(-1\times {{10}^{3}})={{10}^{4}}V\]
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