A) 25 H
B) 5 H
C) 15 H
D) 35 H
Correct Answer: C
Solution :
(c) 15 H Here, \[{{\mu }_{r}}=6000,\,\,l=30\,cm=0.3\,m,\,N=2000,\] \[A=1.5\,c{{m}^{2}}=1.5\times {{10}^{-4}}{{m}^{2}}\] \[L=\frac{{{\mu }_{r}}{{\mu }_{0}}{{N}^{2}}A}{l}\] \[=\frac{6000\times 4\pi \times {{10}^{-7}}\times {{(2000)}^{2}}\times 1.5\times {{10}^{-4}}}{0.3}\] \[=15\,H\]You need to login to perform this action.
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