A) 0.5 J
B) 0.4 J
C) 1 J
D) 0.1 J
Correct Answer: B
Solution :
(b) 0.4 J Here, \[L=200\,\,mH=200\times {{10}^{-3}}H,l=2A\] As \[U=\frac{1}{2}L{{l}^{2}}=\frac{1}{2}\times (200\times {{10}^{-3}})\times {{2}^{2}}=0.4J\]
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