12th Class Physics Electro Magnetic Induction Question Bank MCQ - Electromagnetic Induction

  • question_answer
    By a change of current from 5 A to 10 A in 0.1 s the self induced emf is 10 V. The change in the energy of the magnetic field of a coil will be:

    A) 5 J                   

    B) 6 J     

    C) 7.5 J                            

    D) 9 J

    Correct Answer: C

    Solution :

    (c) 7.5 J             \[\left| \varepsilon  \right|=L\frac{\Delta l}{\Delta t}\]             \[L=\frac{\left| \varepsilon  \right|\Delta t}{\Delta l}+\frac{10\times 0.1}{(10-5)}=0.2\,H\] The magnetic field energies for currents \[{{l}_{1}}\] and \[{{l}_{2}}\] are             \[{{U}_{1}}=\frac{1}{2}Ll_{1}^{2}\] and \[{{U}_{2}}=\frac{1}{2}Ll_{2}^{2}\] Change in energy, \[\Delta U={{U}_{2}}-{{U}_{1}}\]             \[=\frac{1}{2}Ll_{2}^{2}-\frac{1}{2}Ll_{1}^{2}=\frac{L}{2}(l_{2}^{2}-l_{1}^{2})\]             \[=\frac{0.2}{2}({{10}^{2}}-{{5}^{2}})=7.5\,J\]


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