A) \[4.2\times {{10}^{-8}}V\]
B) \[2.8\times {{10}^{-8}}V\]
C) \[7.3\times {{10}^{-6}}V\]
D) \[3.8\times {{10}^{-6}}V\]
Correct Answer: D
Solution :
(d) \[3.8\times {{10}^{-6}}V\] Here, \[\frac{N}{l}=10\] turns per cm = 1000 turns per metre \[A=3\,c{{m}^{2}}=3\times {{10}^{-4}}{{m}^{2}}\] or \[\frac{dl}{dt}=\frac{4-2}{0.2}=10\,A\,{{s}^{-1}}\] Also \[\varepsilon =\frac{d\phi }{dt}=\frac{d}{dt}(BA)=A\frac{d}{dt}\left( {{\mu }_{0}}\frac{N}{l}I \right)=A{{\mu }_{0}}\left( \frac{N}{l} \right)\frac{dI}{dt}\] \[=3\times {{10}^{-4}}\times 4\pi \times {{10}^{-7}}\times 1000\times 10=3.8\times {{10}^{-6}}V\]You need to login to perform this action.
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