A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{2}\]
C) \[\frac{-\pi }{6}\]
D) \[\pi \]
Correct Answer: B
Solution :
(b) \[\frac{\pi }{2}\] We know that flux linked with the coil \[\phi =BA\,\,\cos \,\theta \] Induced emf, \[\varepsilon =-\frac{d\phi }{dt}=-\frac{d(BA\,cos\,\theta )}{dt}=BA\,\sin \,\theta \] \[=BA\,\,\cos \left( \frac{\pi }{2}+\theta \right)\] \[\therefore \] Phase difference \[=\frac{\pi }{2}+\theta -\theta =\frac{\pi }{2}\]You need to login to perform this action.
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