A) 1 : 1
B) 1 : 2
C) 2 : 1
D) 1 : 3
Correct Answer: A
Solution :
(a) 1 : 1 Half of the energy provided by the source is dissipated during charging a capacitor and other half stored in capacitor. \[\therefore \,\,\frac{Energy\text{ }stored\text{ }in\text{ }a\text{ }capacitor}{Energy\text{ }dissipated\text{ }during\text{ }charging\text{ }a\text{ }capacitor}=\frac{1}{1}\]You need to login to perform this action.
You will be redirected in
3 sec