A) W/4
B) W/2
C) 2W
D) 4W
Correct Answer: D
Solution :
(d) 4W Energy stored in a capacitor, \[W=\frac{{{Q}^{2}}}{2C}\] Now, if charge Q increases to 2Q, then energy stored \[W'=\frac{{{\left( 2Q \right)}^{2}}}{2C}=\frac{4{{Q}^{2}}}{2C}=4W\]You need to login to perform this action.
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