A) \[{{10}^{5}}A\]
B) \[{{10}^{6}}A\]
C) \[{{10}^{7}}A\]
D) \[{{10}^{8}}A\]
Correct Answer: A
Solution :
(a) \[{{10}^{5}}A\] As \[Bl={{\mu }_{0}}Ml={{\mu }_{0}}(l+{{l}_{M}})\] Here, \[l=0\] Then \[{{\mu }_{0}}Ml={{\mu }_{0}}({{l}_{M}})\] \[\Rightarrow {{l}_{M}}=Ml={{10}^{6}}\times 0.1={{10}^{5}}A\]You need to login to perform this action.
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