A) 2.48 T
B) 3.48 T
C) 4.48 T
D) 5.48 T
Correct Answer: C
Solution :
(c) 4.48 T Here, \[r=15\text{ }cm=15\times {{10}^{-2}}m\] \[N=3500\,\,turns,l=12A,{{\mu }_{r}}=800\] Then number of turns/length (n) \[=\frac{N}{2\pi r}=\frac{3500}{2\pi \times 15\times {{10}^{-2}}}=3715.5\] \[B={{\mu }_{0}}{{\mu }_{r}}nl\] \[B=4\pi \times {{10}^{-7}}\times 800\times 3715.5\times 1.2=4.48\,T\]You need to login to perform this action.
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