A) \[(3,5)\]
B) \[(5,3)\]
C) \[(3,-5)\]
D) \[(2,5)\]
Correct Answer: A
Solution :
[a] Required point |
\[=\left\{ \frac{2\times 4+1\times 1}{2+1},\frac{2\times 6+1\times 3}{2+1} \right\}\] |
(By section formula) |
\[=\left( \frac{8+1}{3},\frac{12+3}{3} \right)=\left( \frac{9}{3},\frac{15}{3} \right)=(3,5)\] |
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