A) \[2\ and-1\]
B) \[~1\ and-2\]
C) \[~1\ and\ 2\]
D) \[-~1\ and\ -2\]
Correct Answer: A
Solution :
[a] \[AB=BC\]and A,B and C are collinear. |
\[\therefore \] B is the mid-point of AC. |
By mid-point formula, |
\[(1,3)=\left( \frac{3+b}{2},\frac{a+4}{2} \right)\] |
On comparing x and y-coordinates, we get |
\[1=\frac{3+b}{2}\Rightarrow 3+b=2\Rightarrow b=-1\] |
and\[3=\frac{a+4}{2}\Rightarrow a+4=6\Rightarrow a=2\] |
Hence, \[a=2\] and \[b=-1\]. |
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