A) \[\frac{5}{12}\]
B) \[\frac{7}{12}\]
C) \[\frac{3}{4}\]
D) \[\frac{11}{12}\]
Correct Answer: A
Solution :
| [a]\[\sin \theta =\frac{5}{13}\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\cos \theta =\sqrt{1-{{\sin }^{2}}\theta }=\sqrt{1-{{\left( \frac{5}{13} \right)}^{2}}}=\sqrt{1-\frac{25}{169}}\] |
| \[=\sqrt{\frac{144}{169}}=\frac{12}{13}\] |
| So,\[\tan \theta =\frac{\sin \theta }{\cos \theta }=\frac{5}{13}\times \frac{13}{12}=\frac{5}{12}\] |
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