A) 7
B) 0
C) \[\frac{1}{7}\]
D) 1
Correct Answer: C
Solution :
| [c] Given,\[\sec \theta +\tan \theta =\frac{7}{1}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\frac{(\sec \theta +\tan \theta )(\sec \theta -\tan \theta )}{(\sec \theta -\tan \theta )}=\frac{7}{1}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\sec \theta -\tan \theta =\frac{{{\sec }^{2}}\theta -{{\tan }^{2}}\theta }{7}\] |
| \[[(a+b)\,\,(a-b)={{a}^{2}}-{{b}^{2}}]\] |
| \[\therefore \,\,\,\,\,\,\,\,\,\,\sec \theta -\tan \theta =\frac{1}{7}\]\[[{{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1]\] |
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