A) \[-2\]
B) \[-6\]
C) \[-4\]
D) None of these
Correct Answer: B
Solution :
[b] We have, \[{{3}^{x-y}}=9\Rightarrow \,\,{{3}^{x-y}}={{3}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x-y=2\] ..(1) |
and \[x-2y=6\] ..(2) |
From eq. (1), \[x=y+2\] .....(3) |
Substituting the value of x in eq. (2). we get |
\[y+2-2y=6\,\,\,\Rightarrow \,\,\,-y=4\,\,\,\Rightarrow \,\,\,y=-4\] |
Substituting the value of y in eq. (3), we get |
\[x=-4+2=-2\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x+y=-2+(-4)=-6\] |
You need to login to perform this action.
You will be redirected in
3 sec