A) \[m=-1\]
B) \[m=1\]
C) \[m=-\frac{1}{2}\]
D) \[m=\frac{1}{2}\]
Correct Answer: A
Solution :
[a] The given pair of equations is |
\[3x-2y=4\,\,\,\Rightarrow \,\,\,3x-2y-4=0\] ...(1) |
and \[2x+y=5\,\,\,\Rightarrow \,\,2x+y-5=0\] ...(2) |
Multiplying eq. (2) by 2, we get |
\[4x+2y-10=0\] ...(3) |
On adding eqs. (1) and (2). we get |
\[7x-14=0\,\,\,\Rightarrow \,\,\,x=2\] |
Substituting x = 2 in eq. (1), we get |
\[3(2)-2y-4=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,2y=2\Rightarrow y=1\] |
Now, \[y=x+m\,\,\,\,\Rightarrow \,\,\,1=2+m\,\,\Rightarrow \,\,m=-1\] |
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