A) 6
B) 7
C) 8
D) 9
Correct Answer: B
Solution :
Let the fraction be \[\frac{x}{y}\]. |
Then, according to the question |
\[\frac{x+1}{y+1}=\frac{4}{5}\] |
\[\Rightarrow \,\,\,\,\,\,\,5x+5=4y+4\] |
\[\Rightarrow \,\,5x-4y=-1\] (i) |
and \[\frac{x-5}{y-5}=\frac{1}{2}\] |
\[\Rightarrow \,\,\,\,\,\,2x-10=y-5\] |
\[\Rightarrow \,\,\,\,2x-y=5\] (ii) |
On multiplying Eq. (i) by 2 and Eq. (ii) by 5 and then subtracting Eq. (ii) from Eq. (i), we get |
\[10x-8y=-2\] |
On substituting the value of y in Eq. (i), we get |
\[5x-4\times 9=-1\] |
\[\Rightarrow \,\,\,\,x=-1+36\] |
\[\Rightarrow \,\,\,\,x=7\] |
\[\therefore \] Fraction \[=\frac{7}{9}\] |
Therefore, numerator of this fraction is 7. |
You need to login to perform this action.
You will be redirected in
3 sec