A) 28
B) 30
C) 32
D) 34
Correct Answer: B
Solution :
Let present age of man = x yr |
and present age of son = y yr |
Six years hence, men's age = (x + 6) yr, |
son's age = (y + 6) yr |
According to question, |
\[\left( x+6 \right)=3\left( y+6 \right)\Rightarrow x+6=3y+18\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,x-3y=12\] ...(i) |
and three years ago Men's age = (x - 3) yr, |
son's age = (y - 3) yr |
According to the question, |
\[\left( x-3 \right)=9\left( y-3 \right)\] |
\[\Rightarrow \,\,\,\,x-3=9y-27\] |
\[\Rightarrow \,\,\,\,\,\,\,x-9y=-24\] ...(ii) |
On subtracting Eq. (ii) from Eq. (i), we get |
\[6y=36\Rightarrow \,\,y=6\] |
On substituting the value of y in Eq. (i), |
we get |
\[x-18=12\Rightarrow x=30\,yr\] |
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