A) both positive
B) both negative
C) one positive and one negative
D) can't be determined
Correct Answer: B
Solution :
[b] Let \[\alpha \] and \[\beta \] be the zeroes of\[{{x}^{2}}+25x+156\] . |
Then, \[\alpha +\beta =-25\] and \[\alpha \beta =156\] |
This happens when \[\alpha \] and \[\beta \] are both negative. |
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