A) 0
B) 3
C) 1
D) -3
Correct Answer: B
Solution :
[b] Let \[\alpha \] and \[\frac{1}{\alpha }\] be the roots of \[f(x)=3{{x}^{2}}+11x+p\] |
\[\therefore \] Product of roots \[=\alpha \cdot \frac{1}{\alpha }=\frac{p}{3}\Rightarrow p=3\] |
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