A) 5
B) 4
C) -2
D) -4
Correct Answer: B
Solution :
[b] The given polynomial is |
\[f(x)=2{{x}^{3}}-3k{{x}^{2}}+4x-5\] |
\[\therefore \] Sum of zeroes \[=-\frac{(-3k)}{2}=\frac{3k}{2}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,6=\frac{3k}{2}\] [sum of zeroes is 6 (Given)] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k=4\] |
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