A) \[{{x}^{2}}-\sqrt{3}\]
B) (b)\[{{x}^{2}}+\sqrt{3}\]
C) \[{{x}^{2}}-3\]
D) \[{{x}^{2}}+3\]
Correct Answer: B
Solution :
| [b] It is given that sum of zeroes = 0 |
| Product of zeroes \[=\sqrt{3}\] |
| \[\therefore \] The required polynomial is |
| \[{{x}^{2}}-(\text{Sum of the zeroes)x}+(\text{Product of the zeroes})\] \[={{x}^{2}}-(0)x+\sqrt{3}\]i.e., \[{{x}^{2}}+\sqrt{3}\] |
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