A) \[3\]
B) \[5\]
C) \[2\]
D) \[-1\]
Correct Answer: C
Solution :
[c] Since 1 is a zero of the polynomial |
\[f(x)=2{{x}^{2}}+5x-(3p+1),\]then \[f(1)=0\] |
i.e., \[2{{(1)}^{2}}+5(1)-(3p+1)=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2+5-3p-1=0\Rightarrow p=2\] |
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