A) \[q-1\]
B) \[1-q\]
C) \[q\]
D) \[1+q\]
Correct Answer: B
Solution :
[b] The given polynomial is |
\[f(x)={{x}^{2}}-p(x+1)-q={{x}^{2}}-px-p-q\] Now,\[\alpha +\beta =-\frac{(-p)}{1}=p\]and \[\alpha \beta =\frac{-p-q}{1}=-p-q\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,(\alpha +1)\,(\beta +1)=\alpha \beta +\alpha +\beta +1\] |
\[=-p-q+p+1=1-q\] |
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