A) \[48\,\,c{{m}^{2}}\]
B) \[42.50\,\,c{{m}^{2}}\]
C) \[32.50\,\,c{{m}^{2}}\]
D) \[30.5\,\,c{{m}^{2}}\]
Correct Answer: D
Solution :
\[PR=\sqrt{64+36}=\sqrt{100}=10\,\,cm\] Radius\[=\frac{10}{2}=5\,\,cm\] Now, Area \[=\pi {{r}^{2}}=\pi \times {{\left( 5 \right)}^{2}}=25\pi \] Area of shaded portion\[=\left( 25\pi -8\times 6 \right)\] \[=\left( 25\times \frac{22}{7}-48 \right)=\frac{550-336}{7}=\frac{214}{7}=30.5\,\,c{{m}^{2}}\]You need to login to perform this action.
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