A) \[4\pi \]
B) \[8\pi \]
C) \[10\pi \]
D) None of these.
Correct Answer: C
Solution :
\[AB=CD=2BC=2BP=2CQ\] \[\because \]\[BC=1\times 2=2\,\,cm\] \[\Rightarrow \]\[AB=2BC\] \[\therefore \]\[AB=2\times 2=4\,\,cm\] Now, \[AB=2BP\] \[\therefore \]\[BP=\frac{AB}{2}=2\,\,cm\] Now, \[CD=2BC\] \[\therefore \]\[CD=4\,\,cm\] Now, \[\therefore \]\[CQ=\frac{4}{2}=2\,\,cm\] Total perimeter \[=\left( \frac{1}{2}\times 2\pi \times \frac{2}{2} \right)\times 4+\left( \frac{1}{2}\times 2\pi \times 2 \right)\times 2+2\pi {{(1)}^{2}}\] \[=4\pi +4\pi +2\pi =10\pi \]You need to login to perform this action.
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