A) \[\frac{41}{\sqrt{34}}\,cm\]
B) \[\sqrt{\frac{41}{40}}\,cm\]
C) \[\frac{29}{\sqrt{20}}\,cm\]
D) \[\frac{20}{\sqrt{29}}\,cm\]
Correct Answer: D
Solution :
[d] Let the altitude be x cm. Then, \[\frac{1}{2}\times 4\times x=20\] \[\Rightarrow \] \[x=10\,cm\] BC = Hypotenuse\[=\sqrt{{{(10)}^{2}}+{{(4)}^{2}}}\] \[=\sqrt{116}=\sqrt{4\times 29}=2\sqrt{29}\] Let \[AD\bot BC.\]Then, \[\frac{1}{2}\times BC\times AD=\] area of \[\Delta ABC\] \[\Rightarrow \] \[\frac{1}{2}\times 2\sqrt{29}\times AD=20\] \[\therefore \] \[AD=\frac{20}{\sqrt{29}}\,cm\] |
You need to login to perform this action.
You will be redirected in
3 sec