A) 0.525 cm
B) 4.2 cm
C) 4.41 cm
D) 8.4 cm
Correct Answer: B
Solution :
[b] The areas of two similar triangles are in the ratio of the squares of the corresponding heights. \[\frac{12}{48}=\frac{{{(2.1)}^{2}}}{{{h}^{2}}}\] \[\Rightarrow \] \[{{h}^{2}}=4\times {{(2.1)}^{2}}\] \[\Rightarrow \] \[h=(2\times 2.1)=4.2\,cm\] |
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