A) 0.805 M, 4.83 N, 0.825 M
B) 0.825 M, 48.3 N, 0.805 M
C) 4.83 M, 4.83 N, 4.83 M
D) None
Correct Answer: A
Solution :
Molarity \[=\frac{%\times 10\times d}{GMM}\] \[=\frac{22\times 10\times 1.253}{342}=0.805M\]. Normality \[=\frac{%\times 10\times d}{GEM}\] \[=\frac{22\times 10\times 1.253}{342/6}=4.83N\] Molality \[=\frac{22\times 1000}{342(100-22)}=0.825m\]You need to login to perform this action.
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