A) Add \[0.585\,g\,NaCl\]
B) Add \[20\,ml\] water
C) Add \[0.010ml\,NaCl\]
D) Evaporate \[10ml\] water
Correct Answer: A
Solution :
100 ml. of 0.30M\[=\frac{100\times 0.3}{1000}=0.03\] mole of NaCl 100 ml of 0.40M \[=\frac{100\times 0.4}{1000}=0.04\] mole of NaCl Moles of NaCl to be added \[=0.04-0.03=0.01\,\text{mole}\] = 0.585 gmYou need to login to perform this action.
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