A) \[\left\{ -2,2 \right\}\]
B) \[\left\{ 1 \right\}\]
C) \[\left\{ -2 \right\}\]
D) \[\left\{ 2 \right\}\]
Correct Answer: C
Solution :
[c] As \[(\lambda +1){{x}^{2}}+2=\lambda x+3\]has only one solution, so D=0 |
\[\Rightarrow {{\lambda }^{2}}-4(\lambda +1)(-1)=0\] Or \[{{\lambda }^{2}}+4\lambda +4=0\] Or \[{{(\lambda +2)}^{2}}=0\] |
\[\therefore \lambda =-2\] |
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