A) 0
B) \[\pi \]
C) \[\pi /2\]
D) none of these
Correct Answer: C
Solution :
[c] \[\left| k+{{z}^{2}} \right|=\left| {{z}^{2}} \right|-k=\left| {{z}^{2}} \right|+\left| k \right|\] \[\Rightarrow \] \[k,{{z}^{2}}\] and 0+i0 are collinear \[\Rightarrow \] arg (\[{{z}^{2}}\])= arg (k) \[\Rightarrow \] 2 arg (z) = \[\pi \] \[\Rightarrow \] arg (z) = \[\frac{\pi }{2}\]You need to login to perform this action.
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