A) \[{{[Mn{{(CO)}_{6}}]}^{+}}\]
B) \[[Fe{{(CO)}_{5}}]\]
C) \[[Cr{{(CO)}_{6}}]\]
D) \[{{[V{{(CO)}_{6}}]}^{-}}\]
Correct Answer: B
Solution :
| [b] |
| (1) \[M{{n}^{+}}=3{{d}^{5}}4{{s}^{1}}.\] In presence of \[CO,\]effective configuration is \[3{{d}^{6}}4{{s}^{0}}.\] |
| \[\Rightarrow \] 3 lone pairs for back bonding with vacant orbital of C in CO. |
| (2) \[F{{e}^{0}}=3{{d}^{6}}4{{s}^{2}}\]. In the presence of \[CO\], effective configuration is\[3{{d}^{6}}\]. |
| \[\Rightarrow \] 4 lone pairs for back bonding with CO. |
| (3) \[C{{r}^{0}}=3{{d}^{5}}4{{s}^{1}}\]. In the presence of CO, effective configuration is \[3{{d}^{6}}.\] |
| \[\Rightarrow \] 3 lone pairs for back bonding with CO. |
| (4) \[{{V}^{-}}=3{{d}^{4}}4{{s}^{2}}.\] In the presence of CO. effective configuration is \[3{{d}^{6}}.\] |
| \[\Rightarrow \] 3 lone pairs for back bonding with CO. |
| These maximum back bonding in \[[Fe{{(CO)}_{5}}]\], therefore CO bond order is lowest |
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