A) 1
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[2\]
Correct Answer: C
Solution :
[c] When a charged particle (charge q, mass m) enters perpendicularly in a magnetic field [b] then, radius of the path \[r=\frac{mv}{qB}\Rightarrow mv=q\beta r.\] Also de Broglie wavelength, \[\lambda =\frac{h}{mv}\] \[\Rightarrow \lambda =\frac{h}{qBr}\Rightarrow \frac{{{\lambda }_{\alpha }}}{{{\lambda }_{p}}}=\frac{{{q}_{p}}{{r}_{p}}}{{{q}_{\alpha }}{{r}_{\alpha }}}=\frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec