A) 2
B) 1
C) \[\sqrt{2}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: C
Solution :
[c] \[K.E.=2{{E}_{0}}-{{E}_{0}}=(for0\le x\le 1)\] \[\Rightarrow {{\lambda }_{1}}=\frac{h}{\sqrt{2m{{E}_{0}}}}\] \[K.E.=2{{E}_{0}}(for\,x>1)\] \[\Rightarrow {{\lambda }_{2}}=\frac{h}{\sqrt{4m{{E}_{0}}}}\Rightarrow \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{2.}\]You need to login to perform this action.
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