A) 1 m
B) 19 m
C) 50 m
D) 75 m
Correct Answer: A
Solution :
\[u=10m/s\] retardation is\[2m/{{s}^{2}}\] Distance travelled in 3th sec is \[{{S}_{nth}}=U+\left( \frac{a}{2} \right)(2n-1)\] \[=10+\left( -\frac{2}{2} \right)(2\times 5-1)=10-(10-1)\] \[=10-9=1m\]You need to login to perform this action.
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