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  5. Time and Motion

9th Class Science Time and Motion Question Bank Motion IIT JEE Objective Problems

  • question_answer
    A particle starts moving from the position of rest under a constant acceleration. It travels a distance 'x' in the first 10s, a distance 'y' in the next 10s then

    A)  \[y=3x\]                             

    B)  \[y=2x\]

    C)  \[y=x\]               

    D)  \[y=4x\]

    Correct Answer: D

    Solution :

    \[X=\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\times a\times 100=50a\] \[Y=\frac{1}{2}a{{(20)}^{2}}=\frac{1}{2}a(400)=200a\] \[\frac{X}{Y}=\frac{50a}{200a}\] \[Y=4x\]


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