A) \[v=u+a{{t}^{2}}\]
B) \[v=u+\frac{a{{t}^{2}}}{2}\]
C) \[v=u+at\]
D) \[v=u\]
Correct Answer: B
Solution :
Acceleration\[=at\] Increase in velocity = Area of \[\Delta OAB\] \[=\frac{1}{2}\times at\times t\] \[=\frac{1}{2}a{{t}^{2}}\] \[\therefore \] \[v=u+\frac{1}{2}a{{t}^{2}}\]You need to login to perform this action.
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