A) \[\frac{{{u}^{2}}}{2g}\]
B) \[\frac{u}{2g}\]
C) \[2{{u}^{2}}g\]
D) none of these
Correct Answer: A
Solution :
From\[~{{v}^{2}}={{u}^{2}}=2as\] \[\therefore \] \[0={{u}^{2}}-2gh\] \[\Rightarrow \] \[h=\frac{{{u}^{2}}}{2g}\]You need to login to perform this action.
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