A) 16 m/s
B) 15 m/s
C) 14 m/s
D) 12m/s
Correct Answer: C
Solution :
From \[{{v}^{2}}={{u}^{2}}-2gh\] \[0={{u}^{2}}-2\times 9.8\times 10\] \[\Rightarrow \] \[{{u}^{2}}=196\] \[\Rightarrow \] \[u=14\,\,m/s\]You need to login to perform this action.
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