A) 0°
B) 90°
C) 180°
D) None of the above
Correct Answer: B
Solution :
\[\cos \theta =\frac{\vec{A}.\vec{B}}{|\vec{A}||\vec{B}|}=\frac{-2+6-4}{\sqrt{14}\sqrt{21}}=0\] \ \[\theta =90{}^\circ \]You need to login to perform this action.
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