A) 30°
B) 45°
C) 60°
D) 90°
Correct Answer: C
Solution :
\[(\hat{i}+\hat{j}).(\hat{j}+\hat{k})=0+0+1+0=1\] \[\cos \theta =\frac{\vec{A}.\vec{B}}{|\vec{A}||\vec{B}|}=\frac{1}{\sqrt{2}\times \sqrt{2}}=\frac{1}{2}\]\ \[\theta =60{}^\circ \]You need to login to perform this action.
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