A) 0.25
B) 25.00
C) 24.50
D) 2.45
Correct Answer: C
Solution :
Mol. weight of \[{{H}_{2}}S{{O}_{4}}=98\] Since, \[1\]mole of \[{{H}_{2}}S{{O}_{4}}\] contains\[98\,\,gm\] \[\therefore \]\[0.25\] mole of \[{{H}_{2}}S{{O}_{4}}\] contains \[=98\times 0.25\] \[\mathbf{=24}\mathbf{.50}\,\,\mathbf{gm}\]You need to login to perform this action.
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